I created an array of a sequence of numbers. How can I check the size of each element, and depending on the number of digits, each element has I want to add more numbers to it. Below I have some code that accomplishes this using one variable, but I want to do it with the array
#array I would like to use start=0 end=20 myarray=( $(seq $start $end) ) #example of how I accomplish this using a variable. checks if the number of integers is between 1-5 and adds some numbers to the end. I would like to accomplish this but with an array. number=2 local newnum=`expr length "$number"` #get lenght of the variable if [ "$newnum" -eq "1" ];then number="0000${number}" elif [ "$newnum" -eq "2" ];then number="000${number}" elif [ "$newnum" -eq "3" ];then number="00${number}" elif [ "$newnum" -eq "4" ];then number="0${number}" elif [ "$newnum" -eq "5" ]; then echo "you enter five numbers" #number remains the size else exit fi #end if 1 Answer
One way:
for val in "${myarray[@]}" do len=${#val} echo $val , $len ....do action depending on $len ..... done 
