#!/bin/bash cd /pg file=`ls -l |awk '{print $9}'` list=() for i in $a do echo $i a=`cat /pg/$i | head -n 1 |awk '{print $8}' ` #output: first interation 15 & 2nd values 60 list+=($a) #a1=`cat /pg/$i | head -n 2 |awk '{print $8}'` done echo $list through this a=`ls -l |awk '{print $9}'` I'm getting two file and iterating through for loop and appending values to list() the list should contains "15","16" but list contains only one value is "15" Please help me to fix the same.
2 Answers
To access the whole array, use
echo "${list[@]}" Using just $list is equivalent to ${list[0]}, i.e. it only shows the first element.
# create list hosts1=() hosts2=() # add hosts hosts1+=( host1 ) hosts1+=( host2 ) hosts2+=( host3 ) hosts2+=( host4 ) # combine 2 lists hosts1+=( ${hosts2[@]} ) # add some more echo ${hosts1[@]} hosts1+=( host5 ) hosts1+=( host6 ) echo ${hosts1[@]} 
