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Ternary conditional operator in Python
I want to do the following in python:
while( i < someW && j < someX){ int x = A[i] > B[j]? A[i++]:B[j++]; .... } Clearly, when either i or j hits a limit, the code will break out of the loop. I need the values of i and j outside of the loop.
Must I really do
x=0 ... if A[i] > B[j]: x = A[i] i+=1 else: x = B[j] j+=1 Or does anyone know of a shorter way?
Besides the above, can I get Python to support something similar to
a,b=5,7 x = a > b ? 10 : 11 2 Answers
The most readable way is
x = 10 if a > b else 11 but you can use and and or, too:
x = a > b and 10 or 11 The "Zen of Python" says that "readability counts", though, so go for the first way.
Also, the and-or trick will fail if you put a variable instead of 10 and it evaluates to False.
However, if more than the assignment depends on this condition, it will be more readable to write it as you have:
if A[i] > B[j]: x = A[i] i += 1 else: x = A[j] j += 1 unless you put i and j in a container. But if you show us why you need it, it may well turn out that you don't.
Try this:
x = a > b and 10 or 11 This is a sample of execution:
>>> a,b=5,7 >>> x = a > b and 10 or 11 >>> print x 11 
