Using Unsigned int 32 bit in Java? [duplicate]

Possible Duplicate:
Converting 32-bit unsigned integer (big endian) to long and back

I want to translate this expression in Java

char tab[100]; tab[10] = '\xc0'; tab[48] = '\x80'; uint32_t w = 0x67452301; uint32_t x = 0xefcdab89; uint32_t y = 0x98badcfe; uint32_t z = 0x10325476; a = ((b & c) | (~b & d)) + (*(uint32_t*)(tab+0x00)) + a - 0x28955B88; a = ((a << 0x07) | (a >> 0x19)) + b; 

I'have tried this but...

char[] tab = new char[64]; tab[10] = (char) 0xc0; tab[48] = (char) 0x80; 

but the value is not the right one, is there another way to assign \0x80 in a char[] ? How can i interprete this kind of cast in java ((uint32_t)) ?

Many thanks !

1 Answer

Type int is 4 bytes, i.e. 32 bits in java. So the regular 32bits int from C may be translated as regular int in java.

Unsigned int is not supported by java language, so use long that contains 8 bytes to represent unsigned 32 bit variables from C.